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n^2+10n-144=0
a = 1; b = 10; c = -144;
Δ = b2-4ac
Δ = 102-4·1·(-144)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*1}=\frac{-36}{2} =-18 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*1}=\frac{16}{2} =8 $
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